begin;
    comment  'LIBRARY' 1
    ;
    Boolean B;
    real X;
    integer array A[+1 : .6⏨2];
    integer I, N;
    B := false;
    N := ⏨+2 × .6;
    X := 0;
    comment    
    ;
    begin;
        comment    
        ;
        own real  array C0[0 : 1];
        procedure P(A, B, C); 
          value A;
          integer A;
          string B;
          Boolean array C;
        begin;
            begin;
                C[(1)] := true ∨ .8 > C0[if true then 0 else 1];
                C[-(-2)] := false ∧ .4 ≥ X + 500⏨-2;

* Syntax error at: C(/.3&1/):=.3#(0)and(if&1#&4thentrueelsefalse);




* Syntax error at: iffalsethenP(A,<STRING>,C)else;



            end;
            ;
            for I := 1 step 1 until 3 do
              begin;
                if .3 ≤ 6 ÷ 2 then goto OUT;
                OUT: ;
            end;
        end;
        real procedure A0L;
        A0L := if X < X then ⏨4 else .6;
        integer procedure II;
        II := +1 × (3 ÷ (4)) - ⏨2 + A0L;
        begin;
            Boolean array C[II + II ÷ II ÷ II : 1.0 ↑ II + 3];
            C0[0] := if B ∧ (1) = (2) then 0 else 0;

* Syntax error at: P(+1)L:(<>)M:(C);



            I := -N - I × N ÷ N ↑ 1;
            goto if 1 - .9 = II ÷ 6 ∧ II ≤ A0L then L else L1;
            L: L1: for I := I step N until II do ;
            if +.3 + ⏨2 = +(.3) then B := ¬B ≡ false else B := ⏨1 > 3 ≡ true;
            for I := ((1)) step +(1) until +60 do
              begin;
                A[⏨1 - 9] := 1 ÷ .1 - 0.1;

* Syntax error at: A(/I/):=if(true)orA(/1/)-1#A(/&1-9/)*1implfalsethen+1else-1;



            end;
            for I := 1,
                     -9 + A[1] step -9 + A[1] until .6⏨1 do
              N := if +A[1] + 0 = A[1] then 0 else ⏨1 - 9 + N;

* Syntax error at: if+N#+1equivN=-Nor0<+Nand0+N>=0thenelsegotoL2;



            B := B ⊃ N > +0 ≡ 0 < -A[1] ÷ ⏨1 ∨ true;
            L2: goto (L3);

* Syntax error at: L3:B:=trueandfalseorfalseimpltrueequiv+0#-1;



            N := 1 ↑ N × 1 + (⏨1) × ⏨-2 ↑ (1) ÷ (2) + N;
            B := true ≡ -(0) ÷ 1 > -A[1] ∨ ¬true ≡ ¬true;

* Syntax error at: B:=notfalseequiv.1=1impltrueimpl0#1;



            for I := 1 while true do
              goto EXIT;
            EXIT: for I := I while false do
              if -0 ≥ +6 then for N := 1 while 0 ≥ -1 ∨ +N ≤ +(1) do
              for N := 1 do ;
            B := 0 < ⏨1 ⊃ +1 ≤ .1 ∨ -3 ≤ -6 ∧ true ∧ +1 ≤ ⏨1;
            B := B ⊃ -(1) < (2) ≡ ⏨1 = .1 ∧ -(1) ≤ 0;
            if C[1] ⊃ ¬+1 = ⏨1 then ;
            X := A[1] ↑ .5 ↑ ⏨1 + (if ¬N ≥ .1 ∨ (if true then false else true) then -1 else +2);
            begin;
                integer procedure A0(B, C);
                  Boolean B, C;
                A0 := if B ⊃ ¬C then (1) ↑ 2 else if C ∧ ¬B then (1) else (2);
                X := X + A0(true, false) + A0(false, true ⊃ .4 < .6);
                N := X × A0(¬0 = ⏨1, 1 ≥ ⏨2) - A0(¬-1 > .1, ¬.1 ≤ (1));
            end;
            begin;
                goto L4;
                L4: begin;
                    for I := I step if 1 < 2 then 1 else 2 until -10 do ;
                end;

* Syntax error at: ififBthen.1>&1elsenot&1#.6thenbegin;



                X := X + 100;
            end else for I := 1 step .3⏨1 until if ¬(false) then 1 else A[1] do
              B := true;
        end;
        B := false;
    end;
    begin;
        real Y;
        array D[C0[0] : +A[1] ÷ 1 + 1 + C0[0]];
        Boolean procedure B1;
        begin;
            own Boolean  X;
            X := if D[0] < 0 then ¬D[0] ≤ (0) ⊃ (D[0] ≥ (1)) else B;

* Syntax error at: B:=Xand&1+D(/0/)>(1)equiv(D(/0/)#0);



            B1 := B ∨ ⏨1 + D[0] = D[0] ≡ (1) > D[0];
        end;
        switch S := L10, L11;
        D[0] := 0;

* Syntax error at: B:=B1impl&1+(1)#D(/0/)andB;



        L10: ;
        L11: ;
        ;
    end;
    begin;
        switch SS := LA, LB;
        own integer  P;
        procedure Q(L);
          label L;
        begin;
            array R[(0) : -(-1)], S[1 : ⏨1];
            for I := 0,
                     +1,
                     .3,
                     ⏨1,
                     (2),
                     if B then 0 else 1 do
              begin;
                ;
            end;
            for I := 1 while I + (0) ≥ 9,
                     I + 1 while +I < 10 do S[I] := 0;
            for I := 1 + S[2] while -I > 0,
                     I + (1) while ¬I ≥ 10 do
              if B then ;
        end;
        Q(LA);
        LA: ;
        LB: ;
        ;
    end;
    begin;
        procedure P;
        begin;
            ;
            for I := 1 while if 1 < 2 then 0 = A[1] else (A[1]) > 0 do ;
        end;
        array D[1 : if 1 < 2 then 2 else 1];
        for I := 1 while .1 < -3,
                 I + 1 while (I) < 3 do D[I] := I;
        for I := D[2],
                 1 step (1) until (1) do
          if 1 < 2 then L:  else begin;
            ;
        end;
        P;
        for I := 1 step ⏨1 - 9 until ⏨1 - 9,
                 1 while ⏨1 > 11 do X := X + N;
    end;
    OUTREAL(99, X + N);
    ;
end;
end;